how to add different values for each select dropdown options for different rows of a table using custom script. Currently when i set the drop down for each row using the following code: var q_options = []; frappe.model.with_doc(“Quality Checks”, row.specification, function() { var optiontable= f…

Hi can you explain your usecase why you need to add different values for each select?

Check this thread [image] [Tutorial] set_df_property for child table fields? Frappe Framework How to set property of field in child table? Ans: We can set property of doc fields using following syntax. cur_frm.set_df_property(FIELDNAME, Property, Value); e.…

I want to perform Quality Inspection for all items that i procure, and for the quality inspection i have the label and the options. i fetch the label from options from Quality Checks DocType, I am able to fetch the Quality check parameters for each quality attribute in an array. now when i assign t…

have seen this. This does not apply the select options to each row.

I’ve done it by setting the value on each child row render. I did it for changing the read only status, but it should also work for other attributes. frappe.ui.form.on('Document Change Notice Department', { form_render:function(frm, cdt, cdn){ erpnext.document_change_notice.protect_approval_grid…

@Vinod_Gangal I am also facing the same issue. Have you found out any solution for this.??

@Vinod_Gangal I have been facing the same problem, any updates on this?

Thanks! Following Ben’s example I got it to work. Just change the ‘options’ attribute instead of ‘read_only’. for(var i = 0; i < docfield.length; i++) { if(docfield[i].fieldname == "serial_number"){ docfield[i].options = new_serial_number_options; } } grid_row.refresh();

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How to add different values for each select dropdown options for different rows of a table

Sangram June 12, 2017, 8:07am 3

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