How change status of child doctype based on parent doctype sytatus

i have parent doctype which name ‘issue’ on that there is on workflow

when workflow status equal to ‘Completed’ then all this employee in this child doctype table ‘status’ change to ‘Completed’


how to achieve this

import frappe

def on_update(doc, method):
    if doc.workflow_state == "Completed":
        for child in doc.technician:  
            child.status = "Completed"
        doc.save()  

you can write a script like this.

Also, you can directly set the script on server script doctype.

i have use this script that script only change the status but not save it

frappe.ui.form.on(‘Issue’, {
// Trigger when the form is loaded or refreshed
refresh: function(frm) {
update_custom_technician_status(frm);
},
onload: function(frm) {
update_custom_technician_status(frm);
}
});

function update_custom_technician_status(frm) {
// Check if workflow state is ‘Completed’
if (frm.doc.workflow_state == ‘Completed’) {
// Loop through the ‘custom_technician’ table and update ‘status’ field
$.each(frm.doc.custom_technician || , function(index, technician) {
technician.status = ‘Completed’;
});

    // Refresh the custom_technician table to reflect the changes
    frm.refresh_field('custom_technician');
    
    // Save the custom_technician table and the Issue doctype
    frm.save()
        .then(() => {
            // Reload the document after saving
            frappe.msgprint(__('Issue and technician statuses updated.'));
            frm.reload_doc();
        })
        .catch((err) => {
            console.log(err);
            frappe.msgprint(__('Error updating issue or technician status.'));
        });
}

}

my scenario is in this table show those employee only whose status is ‘Completed’
using this script status change to completed but in this table that completed status employee not show