I us following syntax but it doesn’t worked
1.frappe.utils.filter_dict(frm.fields_dict[“readings”].grid.docfields, {“fieldname”: “parameter_value”})[0].options = r.message;
2.var df=frappe.meta.get_docfield(‘Quality Inspection Reading’,‘parameter_value’,frm.doc.name);
df.options=r.message;
I have the same problem
i try this but it doesn’t worked for me, after version-13 stable update it’s doesn’t working
frm.fields_dict.readings.grid.update_docfield_property(
‘parameter_value’,
‘options’,
[‘’].concat(r.message)
);
frappe was changing upper function prototype, but it seems you provide reliable solution @ajay374-J thanks for it
editing for more clarity

frm.fields_dict.child_table_name.grid.update_docfield_property(
“field_name”,
“options”,
[“”].concat([“val 1”, “val 2”, “val 3”])
);
It works and change the field_name over all the child table; If i want the change only for the current row
upon certain condition??
use below code it works for me
frappe.utils.filter_dict(cur_frm.fields_dict[“childtablename”].grid.grid_rows_by_docname[cdn].docfields, { “fieldname”: “fieldname” })[0].options = bindlisthere;
cur_frm.refresh();
did u find solution for this, pls?
I had the same issue, i wanted to dynamically set the options for select field in my childtable.
Here is how i did it,
frappe.ui.form.on("Child Table Doctype",{
field_in_table(frm){
// 1. get the row that is being added or modified
let row = frappe.get_doc(cdt,cdn)
// 2. get the docfield metadata object, this way we can modify the `options` property of the docfield
let df = frappe.meta.get_docfield("Child Table Doctype","child_table_field_name",row.name)
// 3. set the options field with an array of options that you want
df.options = ["your","options","will","go","here"]
// 4. refresh the row to see the changes
frm.fields_dict["child table name in parent doctype"].grid.refresh_row(row.name)
}
})
Hope this helps.